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A 4 M sodium hydroxide solution has density 1.16 g mL−1. What is its approximate molality?

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Answer and explanation

Correct answer: 4.00 mol kg−1

Molarity refers to moles per litre of solution, while molality refers to moles per kilogram of solvent. Take 1 L solution: it contains 4 mol NaOH, whose mass is 4 × 40 = 160 g. The solution mass is 1.16 × 1000 = 1160 g, so water mass is 1160 − 160 = 1000 g = 1 kg. Thus molality = 4/1 = 4.00 mol kg−1, making option C correct. The density is essential for finding solvent mass.

Tags

molaritymolalitysodium hydroxidedensityMole concept and molar massSome Basic Concepts of ChemistryChemistryClass 11 MCQ

Frequently asked questions

What is the correct answer to this question?

4.00 mol kg−1

Why is this the correct answer?

Molarity refers to moles per litre of solution, while molality refers to moles per kilogram of solvent. Take 1 L solution: it contains 4 mol NaOH, whose mass is 4 × 40 = 160 g. The solution mass is 1.16 × 1000 = 1160 g, so water mass is 1160 − 160 = 1000 g = 1 kg. Thus molality = 4/1 = 4.00 mol kg−1, making option C correct. The density is essential for finding solvent mass.

Which subject and chapter does this question cover?

This is a Class 11 Chemistry question. Chapter: Some Basic Concepts of Chemistry. Topic: Mole concept and molar mass.

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