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15 g solute is dissolved to make 300 mL solution. If molar mass of solute is 75 g per mol, what is the molarity of the solution?
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Answer and explanation
Correct answer: 0.67 mol L^-1
The amount of solute is 15/75 = 0.20 mol. The final solution volume must be converted to litres: 300 mL = 0.300 L. Hence molarity = moles of solute/final volume = 0.20/0.300 = 0.667 mol L^-1, which rounds to 0.67 mol L^-1. Molarity uses solution volume, not solvent volume.
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What is the correct answer to this question?
0.67 mol L^-1
Why is this the correct answer?
The amount of solute is 15/75 = 0.20 mol. The final solution volume must be converted to litres: 300 mL = 0.300 L. Hence molarity = moles of solute/final volume = 0.20/0.300 = 0.667 mol L^-1, which rounds to 0.67 mol L^-1. Molarity uses solution volume, not solvent volume.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
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