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12 g urea is dissolved in 200 g water. Molar mass of urea is 60 g per mole. What is the molality?

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Answer and explanation

Correct answer: 1.0 mole per kilogram

Molality uses the moles of solute and the mass of solvent, not the total solution mass. Moles of urea = 12 g ÷ 60 g mol−1 = 0.20 mol. The water mass is 200 g = 0.200 kg. Therefore, m = 0.20 ÷ 0.200 = 1.0 mol kg−1, so option A is correct. The other choices result from using an incorrect mass or calculation.

Tags

molalityureaconcentrationsolutionsChapter 01: Solutionschapter 01 solutionsChemistryClass 11 MCQ

Frequently asked questions

What is the correct answer to this question?

1.0 mole per kilogram

Why is this the correct answer?

Molality uses the moles of solute and the mass of solvent, not the total solution mass. Moles of urea = 12 g ÷ 60 g mol−1 = 0.20 mol. The water mass is 200 g = 0.200 kg. Therefore, m = 0.20 ÷ 0.200 = 1.0 mol kg−1, so option A is correct. The other choices result from using an incorrect mass or calculation.

Which subject and chapter does this question cover?

This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.

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