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0.25 mole solute is present in 500 g solvent. What is the molality?

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Answer and explanation

Correct answer: 0.5 mole per kilogram

The governing concept is molality, defined as moles of solute divided by the mass of solvent in kilograms. Convert 500 g of solvent to 0.500 kg, then calculate m = 0.25 mol ÷ 0.500 kg = 0.50 mol kg−1. Therefore, option A is correct. Options B, C, and D result from failing to convert the solvent mass correctly or from reversing the calculation.

Related tags

MolalityConcentrationSolutionsChemistryChapter 01: SolutionsChapter 01 SolutionsClass 11 Mcq

Frequently asked questions

What is the correct answer to this question?

0.5 mole per kilogram

Why is this the correct answer?

The governing concept is molality, defined as moles of solute divided by the mass of solvent in kilograms. Convert 500 g of solvent to 0.500 kg, then calculate m = 0.25 mol ÷ 0.500 kg = 0.50 mol kg−1. Therefore, option A is correct. Options B, C, and D result from failing to convert the solvent mass correctly or from reversing the calculation.

Which subject and chapter does this question cover?

This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.

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