0.02 mol solute is present in 500 mL solution. If molar mass of solute is 100 g per mol, what is the mass by volume percentage?
Answer and explanation
Correct answer: 0.4 percent
First convert moles into mass: 0.02 mol × 100 g mol^-1 = 2 g solute. Mass by volume percentage is grams of solute per 100 mL of solution. Therefore percentage = (2/500) × 100 = 0.4%. The denominator is the final solution volume, and the volume must remain in millilitres for this percentage formula.
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What is the correct answer to this question?
0.4 percent
Why is this the correct answer?
First convert moles into mass: 0.02 mol × 100 g mol^-1 = 2 g solute. Mass by volume percentage is grams of solute per 100 mL of solution. Therefore percentage = (2/500) × 100 = 0.4%. The denominator is the final solution volume, and the volume must remain in millilitres for this percentage formula.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
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