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How much water should be added to 100 mL of 5 M solution to prepare a 0.5 M solution?

Answer and explanation

Correct answer: 900 mL

During dilution, the amount of solute remains constant, so M1V1 = M2V2. Substitution gives 5 × 100 mL = 0.5 × V2, hence V2 = 1000 mL. This is the final volume of the diluted solution. The initial volume was 100 mL, therefore the volume of water added is 1000 − 100 = 900 mL. Option C is correct; choosing 1000 mL confuses final volume with added water.

Related tags

DilutionMolarityFinal VolumeWater AdditionMole Concept And Molar MassSome Basic Concepts Of ChemistryChemistryClass 11 Mcq

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