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A pure binary compound contains 72% A by mass. What percentage of the compound’s mass is B?एक शुद्ध द्विघटकीय यौगिक में द्रव्यमान के आधार पर 72% A है। यौगिक के द्रव्यमान का कितना प्रतिशत B है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 28%28%
Because the compound contains only A and B, their mass percentages add up to 100%. Therefore, B is 100% − 72% = 28%.यौगिक में केवल A और B हैं, इसलिए उनके द्रव्यमान प्रतिशतों का योग 100% होगा। अतः B का प्रतिशत = 100% − 72% = 28% है।
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