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A pure compound contains 2 g of element A and 6 g of element B in one sample. How much B should be present in another sample containing 4 g of A?

Answer and explanation

Correct answer: 12 g

The compound has a fixed mass ratio: B/A = 6 g ÷ 2 g = 3. For 4 g of A, the required mass of B is 3 × 4 g = 12 g.

Related tags

ChemistryDefinite ProportionsLaws Of Chemical CombinationSome Basic Concepts Of ChemistryClass 11 Mcq

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