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Why does the solution near the cathode become basic in the chlor-alkali process?

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Answer and explanation

Correct answer: Because hydroxide ions remain in the solution

The governing concept is the cathode reaction in aqueous brine. Water gains electrons at the cathode: 2H₂O + 2e⁻ → H₂ + 2OH⁻. Sodium ions remain in the solution and combine with hydroxide ions to form NaOH, so the region becomes basic. Thus option A is correct. Chlorine forms at the anode, salt does dissolve, and sodium metal is not deposited in water.

Tags

cathodesodium hydroxidechlor-alkali processAcidsBasesand Saltsacids bases and saltsChemical Substances – Nature and Behaviourchemical substances nature and behaviourScience

Frequently asked questions

What is the correct answer to this question?

Because hydroxide ions remain in the solution

Why is this the correct answer?

The governing concept is the cathode reaction in aqueous brine. Water gains electrons at the cathode: 2H₂O + 2e⁻ → H₂ + 2OH⁻. Sodium ions remain in the solution and combine with hydroxide ions to form NaOH, so the region becomes basic. Thus option A is correct. Chlorine forms at the anode, salt does dissolve, and sodium metal is not deposited in water.

Which subject and chapter does this question cover?

This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Acids, Bases, and Salts.

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