Which products are formed when copper(II) oxide is heated with hydrogen gas?
Answer and explanation
Correct answer: Copper and water
On heating, hydrogen removes oxygen from copper(II) oxide to form water, and copper(II) oxide is reduced to copper. The equation is \(\mathrm{CuO + H_2 \xrightarrow{heat} Cu + H_2O}\). Therefore, copper and water are formed. Copper sulphate cannot form because no source of sulfate ions is present in the reaction.
Frequently asked questions
What is the correct answer to this question?
Copper and water
Why is this the correct answer?
On heating, hydrogen removes oxygen from copper(II) oxide to form water, and copper(II) oxide is reduced to copper. The equation is \(\mathrm{CuO + H_2 \xrightarrow{heat} Cu + H_2O}\). Therefore, copper and water are formed. Copper sulphate cannot form because no source of sulfate ions is present in the reaction.
Which subject and chapter does this question cover?
This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Chemical Reactions and Equations.
