Which statement correctly describes oxidation and reduction in the reaction \\(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\\)?
Answer and explanation
Correct answer: CuO is reduced and H₂ is oxidised.
CuO loses oxygen, so it is reduced; the oxidation number of copper changes from \\( +2 \\) to \\(0\\). H₂ gains oxygen to form H₂O, so it is oxidised; the oxidation number of hydrogen changes from \\(0\\) to \\( +1 \\). Therefore, this is a redox reaction, not merely a displacement reaction.
Frequently asked questions
What is the correct answer to this question?
CuO is reduced and H₂ is oxidised.
Why is this the correct answer?
CuO loses oxygen, so it is reduced; the oxidation number of copper changes from \\( +2 \\) to \\(0\\). H₂ gains oxygen to form H₂O, so it is oxidised; the oxidation number of hydrogen changes from \\(0\\) to \\( +1 \\). Therefore, this is a redox reaction, not merely a displacement reaction.
Which subject and chapter does this question cover?
This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Chemical Reactions and Equations.
