Which base remains in the solution during the chlor-alkali process?
Answer and explanation
Correct answer: Sodium hydroxide
In the chlor-alkali process, an aqueous solution of sodium chloride is electrolysed. Chlorine is released at the anode, while water is reduced at the cathode to form hydrogen and hydroxide ions. The sodium ions remaining in solution combine with hydroxide ions, producing sodium hydroxide: 2NaCl + 2H₂O → 2NaOH + Cl₂ + H₂. Thus option A is correct. The other hydroxides are not formed from brine because calcium, magnesium, and ammonium ions are absent.
Frequently asked questions
What is the correct answer to this question?
Sodium hydroxide
Why is this the correct answer?
In the chlor-alkali process, an aqueous solution of sodium chloride is electrolysed. Chlorine is released at the anode, while water is reduced at the cathode to form hydrogen and hydroxide ions. The sodium ions remaining in solution combine with hydroxide ions, producing sodium hydroxide: 2NaCl + 2H₂O → 2NaOH + Cl₂ + H₂. Thus option A is correct. The other hydroxides are not formed from brine because calcium, magnesium, and ammonium ions are absent.
Which subject and chapter does this question cover?
This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Acids, Bases, and Salts.
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