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When gypsum is heated at a controlled temperature, how much water remains in the product formed?

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Answer and explanation

Correct answer: Half a water molecule per calcium sulphate unit

Gypsum has the formula CaSO₄·2H₂O, so it contains two water molecules per calcium sulphate unit. Controlled heating removes one and a half of these water molecules and forms plaster of Paris, CaSO₄·½H₂O. Therefore half a water molecule remains per calcium sulphate unit. The other values do not match the balanced formula or the known dehydration process, so A is correct.

Tags

gypsumplaster of Pariswater of crystallisationAcidsBasesand Saltsacids bases and saltsChemical Substances – Nature and Behaviourchemical substances nature and behaviourScience

Frequently asked questions

What is the correct answer to this question?

Half a water molecule per calcium sulphate unit

Why is this the correct answer?

Gypsum has the formula CaSO₄·2H₂O, so it contains two water molecules per calcium sulphate unit. Controlled heating removes one and a half of these water molecules and forms plaster of Paris, CaSO₄·½H₂O. Therefore half a water molecule remains per calcium sulphate unit. The other values do not match the balanced formula or the known dehydration process, so A is correct.

Which subject and chapter does this question cover?

This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Acids, Bases, and Salts.

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