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What is the correct pair of the gas formed at the cathode and the base remaining in solution in the chlor-alkali process?

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Answer and explanation

Correct answer: Hydrogen and sodium hydroxide

The chlor-alkali process electrolyses concentrated aqueous sodium chloride, or brine. At the cathode, water gains electrons and produces hydrogen gas and hydroxide ions. At the anode, chloride ions produce chlorine gas. The sodium ions remaining in solution combine with hydroxide ions to form sodium hydroxide. Therefore option B is correct; calcium hydroxide, oxygen, carbon dioxide, and ammonium hydroxide are not the products in this process.

Tags

chlor-alkali processelectrolysissodium hydroxideAcidsBasesand Saltsacids bases and saltsChemical Substances – Nature and Behaviourchemical substances nature and behaviourScience

Frequently asked questions

What is the correct answer to this question?

Hydrogen and sodium hydroxide

Why is this the correct answer?

The chlor-alkali process electrolyses concentrated aqueous sodium chloride, or brine. At the cathode, water gains electrons and produces hydrogen gas and hydroxide ions. At the anode, chloride ions produce chlorine gas. The sodium ions remaining in solution combine with hydroxide ions to form sodium hydroxide. Therefore option B is correct; calcium hydroxide, oxygen, carbon dioxide, and ammonium hydroxide are not the products in this process.

Which subject and chapter does this question cover?

This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Acids, Bases, and Salts.

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