When copper(II) oxide is heated with hydrogen gas, what change occurs in the copper(II) oxide?
Answer and explanation
Correct answer: It is reduced to copper
The reaction is \(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\). Oxygen is removed from copper(II) oxide to form water, and \(\mathrm{CuO}\) changes into copper. Removal of oxygen is reduction; therefore, copper(II) oxide is reduced. In contrast, hydrogen gains oxygen to form water, so hydrogen is oxidised.
Frequently asked questions
What is the correct answer to this question?
It is reduced to copper
Why is this the correct answer?
The reaction is \(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\). Oxygen is removed from copper(II) oxide to form water, and \(\mathrm{CuO}\) changes into copper. Removal of oxygen is reduction; therefore, copper(II) oxide is reduced. In contrast, hydrogen gains oxygen to form water, so hydrogen is oxidised.
Which subject and chapter does this question cover?
This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Chemical Reactions and Equations.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
