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A solution had pH $3$. After dilution, its pH became $5$. By what factor did the hydrogen ion concentration decrease?एक विलयन का pH $3$ था। तनुकरण के बाद इसका pH $5$ हो गया। हाइड्रोजन आयन की सांद्रता कितने गुणा घट गई?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Decrease by a factor of $100$गुणक $100$ से घट गई
Use $\text{pH}=-\log_{10}[H^+]$. So
$[H^+] \propto 10^{-\text{pH}}$.
When pH changes from $3$ to $5$:
\[
\frac{[H^+]_{\text{initial}}}{[H^+]_{\text{final}}}=10^{(5-3)}=10^2=100.
\]
So the hydrogen ion concentration decreases by a factor of $100$.हम जानते हैं $\text{pH}=-\log_{10}[H^+]$। इसलिए
$[H^+] \propto 10^{-\text{pH}}$.
जब pH $3$ से $5$ होता है:
\[
\frac{[H^+]_{\text{initial}}}{[H^+]_{\text{final}}}=10^{(5-3)}=10^2=100.
\]
अतः हाइड्रोजन आयन की सांद्रता $100$ के गुणक से घटती है।
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