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A gas first turns lime water milky and removes the milkiness when passed in excess. Which soluble substance forms in excess?

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Answer and explanation

Correct answer: Calcium hydrogen carbonate

The governing concept is the reaction of carbon dioxide with lime water. Carbon dioxide first reacts with calcium hydroxide to form insoluble calcium carbonate, which makes the solution milky: CO₂ + Ca(OH)₂ → CaCO₃ + H₂O. When excess CO₂ is passed, the carbonate reacts further with water and carbon dioxide to form soluble calcium hydrogen carbonate: CaCO₃ + CO₂ + H₂O → Ca(HCO₃)₂. Therefore, option C is correct; calcium carbonate is only the initial precipitate.

Related tags

Lime WaterCarbon DioxideCalcium Hydrogen CarbonateAcidsBasesAnd SaltsAcids Bases And SaltsChemical Substances – Nature And BehaviourChemical Substances Nature And BehaviourScience

Frequently asked questions

What is the correct answer to this question?

Calcium hydrogen carbonate

Why is this the correct answer?

The governing concept is the reaction of carbon dioxide with lime water. Carbon dioxide first reacts with calcium hydroxide to form insoluble calcium carbonate, which makes the solution milky: CO₂ + Ca(OH)₂ → CaCO₃ + H₂O. When excess CO₂ is passed, the carbonate reacts further with water and carbon dioxide to form soluble calcium hydrogen carbonate: CaCO₃ + CO₂ + H₂O → Ca(HCO₃)₂. Therefore, option C is correct; calcium carbonate is only the initial precipitate.

Which subject and chapter does this question cover?

This is a Class 10 Science question. Chapter: Chemical Substances – Nature and Behaviour. Topic: Acids, Bases, and Salts.

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