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Which statement about oxidation and reduction is correct in the given equation?
\(2\mathrm{FeCl_3} + \mathrm{SnCl_2} \rightarrow 2\mathrm{FeCl_2} + \mathrm{SnCl_4}\)

Answer and explanation

Correct answer: The oxidation number of Fe changes from +3 to +2, while that of Sn changes from +2 to +4.

In \(\mathrm{FeCl_3}\), Fe has oxidation number \(+3\), which becomes \(+2\) in \(\mathrm{FeCl_2}\). A decrease in oxidation number is reduction, so Fe is reduced. The oxidation number of Sn increases from \(+2\) in \(\mathrm{SnCl_2}\) to \(+4\) in \(\mathrm{SnCl_4}\); therefore, Sn is oxidised. Hence, option A is correct; both elements are not undergoing the same process.

Related tags

Redox ReactionOxidation NumberIronTinChemical EquationsClass 10 Science

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