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In the reaction \(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\), which of the following statement is correct?

Answer and explanation

Correct answer: Copper(II) oxide is reduced and hydrogen is the reducing agent.

Copper has oxidation number \(+2\) in \(\mathrm{CuO}\) and \(0\) in \(\mathrm{Cu}\), so copper(II) oxide is reduced. Hydrogen changes from \(0\) in \(\mathrm{H_2}\) to \(+1\) in \(\mathrm{H_2O}\); therefore, hydrogen is oxidised and acts as the reducing agent. Thus, option B is correct, not option A, which reverses the roles.

Related tags

Chemical ReactionsRedox ReactionsOxidation NumberReductionReducing AgentClass 10 Science

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