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In the reaction \(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\), which substance is reduced?

Answer and explanation

Correct answer: \(\mathrm{CuO}\)

In \(\mathrm{CuO}\), copper changes from oxidation state \(+2\) to \(0\) in the product \(\mathrm{Cu}\). A decrease in oxidation number indicates reduction, so \(\mathrm{CuO}\) is reduced. In contrast, hydrogen in \(\mathrm{H_2}\) changes from \(0\) to \(+1\) in \(\mathrm{H_2O}\), so \(\mathrm{H_2}\) is oxidised.

Related tags

Chemical ReactionsRedox ReactionsReductionOxidation NumberCopper OxideClass 10 Science

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