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In the reaction \(2\mathrm{FeCl_3} + \mathrm{SnCl_2} \rightarrow 2\mathrm{FeCl_2} + \mathrm{SnCl_4}\), which substance is the reducing agent?

Answer and explanation

Correct answer: \(\mathrm{SnCl_2}\)

The oxidation number of Sn in \(\mathrm{SnCl_2}\) increases from \(+2\) to \(+4\), so \(\mathrm{SnCl_2}\) is oxidised. It donates electrons and reduces \(\mathrm{Fe^{3+}}\) in \(\mathrm{FeCl_3}\) to \(\mathrm{Fe^{2+}}\). Therefore, \(\mathrm{SnCl_2}\) is the reducing agent, whereas \(\mathrm{FeCl_3}\) is the oxidising agent.

Related tags

Redox ReactionReducing AgentOxidation NumberChemical ReactionsClass 10 Science

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