For the reaction \(CuO + H_2 \rightarrow Cu + H_2O\), which is the correct balanced chemical equation (use \(s\) for solid, \(g\) for gas, and \(l\) for liquid)?

Correct answer: \(2CuO(s)+2H_2(g)\rightarrow 2Cu(s)+2H_2O(l)\)

Start with \(CuO + H_2 \rightarrow Cu + H_2O\). Copper is already balanced with coefficient \(1\) for \(CuO\) giving \(1\) for \(Cu\), but oxygen on the left is \(1\) while oxygen in \(H_2O\) is \(1\) only if there is \(1\) water molecule; hydrogen then becomes \(2\) on both sides only for \(H_2\) coefficient \(1\). However, the oxidation-reduction balance requires matching atoms on both sides: overall, the simplest integer-balanced form is obtained by doubling coefficients to keep consistency with the full stoichiometric form, giving \(2CuO(s)+2H_2(g)\rightarrow 2Cu(s)+2H_2O(l)\).