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Which statement correctly describes oxidation and reduction in the reaction \\(\mathrm{CuO + H_2 \rightarrow Cu + H_2O}\\)?

Answer and explanation

Correct answer: CuO is reduced and H₂ is oxidised.

CuO loses oxygen, so it is reduced; the oxidation number of copper changes from \\( +2 \\) to \\(0\\). H₂ gains oxygen to form H₂O, so it is oxidised; the oxidation number of hydrogen changes from \\(0\\) to \\( +1 \\). Therefore, this is a redox reaction, not merely a displacement reaction.

Related tags

Redox ReactionOxidationReductionOxidation NumberCopper OxideHydrogenClass 10 Science

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