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A basic solution has pH $13$ and changes to pH $10$. Approximately how did its basicity change (in terms of OH$^-$ concentration)?

Answer and explanation

Correct answer: It decreased by a factor of $1000$

For basic solutions, $\text{pOH}=14-\text{pH}$ and $[OH^-] \propto 10^{-\text{pOH}}$.
Initial: $\text{pOH}=14-13=1$.
Final: $\text{pOH}=14-10=4$.
So
\[
\frac{[OH^-]_{\text{initial}}}{[OH^-]_{\text{final}}}=10^{(4-1)}=10^3=1000.
\]
Thus the OH$^-$ concentration (basicity) decreased by a factor of $1000$.

Related tags

PhPohBasesHydroxide IonsConcentration Change

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