26 If (m=3^2 \times 5), what is the value of (m)?
Answer and explanation
Correct answer: C. 45
Explanation: Step 1: (3^2=9). Step 2: (9 \times 5=45), so (m=45). Step 3: Keeping the order of powers and multiplication clear reduces mistakes.
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
Correct answer: C. 45
Explanation: Step 1: (3^2=9). Step 2: (9 \times 5=45), so (m=45). Step 3: Keeping the order of powers and multiplication clear reduces mistakes.
Correct answer: B. (2^3 \times 3^3)
Explanation: Step 1: (216=8 \times 27). Step 2: (8=2^3) and (27=3^3), so (216=2^3 \times 3^3). Step 3: Recognising cube numbers is very useful in medium-level questions.
Correct answer: B. 189
Explanation: Step 1: (3^3=27). Step 2: (27 \times 7=189), so the number is (189). Step 3: Remembering small powers helps you calculate faster.
Correct answer: A. (2^2 \times 3^3 \times 5)
Explanation: Step 1: Write (540=54 \times 10). Step 2: (54=2 \times 3^3) and (10=2 \times 5), so (540=2^2 \times 3^3 \times 5). Step 3: Splitting a large number into easy parts is a safe method.
Correct answer: C. 72
Explanation: Step 1: A divisor must not need prime exponents greater than those available. Step 2: (72=2^3 \times 3^2), which is fully present in (2^4 \times 3^2). Step 3: For divisibility, match the exponent of each prime separately.
Correct answer: B. 2
Explanation: Step 1: A trailing zero is formed by a pair (10=2 \times 5). Step 2: The exponent of (2) is (3) and of (5) is (2), so (2) pairs can be formed. Step 3: For trailing zeros, take the smaller exponent of (2) and (5).
Correct answer: A. (2^3 \times 3 \times 5)
Explanation: Step 1: Write (120=12 \times 10). Step 2: (12=2^2 \times 3) and (10=2 \times 5), so (120=2^3 \times 3 \times 5). Step 3: Do not forget to combine repeated prime factors from different parts.
Correct answer: A. 3
Explanation: Step 1: An odd factor must not contain (2). Step 2: Removing (2^5) leaves only (3), so the greatest odd factor is (3). Step 3: For the greatest odd factor, remove all powers of (2).
Correct answer: C. 6
Explanation: Step 1: In a perfect cube, each prime exponent must be a multiple of (3). Step 2: To make (2^2) into (2^3) and (3^2) into (3^3), multiply by (2 \times 3=6). Step 3: For a cube, exponents should be like (3,6,9).
Correct answer: C. 6
Explanation: Step 1: In a perfect square, every prime exponent must be even. Step 2: To make (2^3) into (2^4) and (3) into (3^2), multiply by (2 \times 3=6). Step 3: For a square, increase odd exponents by one to make them even.
Correct answer: C. (2^6)
Explanation: Step 1: Divide (64) repeatedly by (2). Step 2: (64=2 \times 2 \times 2 \times 2 \times 2 \times 2=2^6). Step 3: (4^3) gives the value, but it is not prime factorisation because (4) is not prime.
Correct answer: B. Only prime numbers are bases in prime factorisation
Explanation: Step 1: Prime factorisation means writing a number as a product of prime numbers. Step 2: Therefore, the bases must be prime numbers only. Step 3: Treating (1) as a prime factor is a major mistake.
Correct answer: C. 12
Explanation: Step 1: Add (1) to each exponent for total factors. Step 2: ((2+1)(1+1)(1+1)=3 \times 2 \times 2=12). Step 3: Do not forget primes with exponent (1).
Correct answer: B. (a=3, b=2)
Explanation: Step 1: Write (360=36 \times 10). Step 2: (36=2^2 \times 3^2) and (10=2 \times 5), so (360=2^3 \times 3^2 \times 5). Hence (a=3, b=2). Step 3: Add exponents of repeated prime factors.
Correct answer: A. 2
Explanation: Step 1: The bases in prime factorisation are the prime factors. Step 2: Here the bases are (2) and (3), and the smallest is (2). Step 3: To find the smallest prime factor, do not focus on exponents.
Correct answer: B. (3 \times 5^2)
Explanation: Step 1: Write (75=3 \times 25). Step 2: Since (25=5^2), (75=3 \times 5^2). Step 3: Do not leave (25) in the final answer because it is not prime.
Correct answer: A. 1
Explanation: Step 1: (10=2 \times 5). Step 2: The exponent of (2) is (4) and of (5) is (1), so only (1) pair of (10) can be formed. Step 3: The maximum number of divisions by (10) is decided by the smaller exponent.
Correct answer: B. Perfect square
Explanation: Step 1: In a perfect square, all prime exponents are even. Step 2: Here every exponent is (2), so (n) is a perfect square. Step 3: To identify a perfect square, check whether exponents are even.
Correct answer: B. Perfect cube
Explanation: Step 1: In a perfect cube, all prime exponents are multiples of (3). Step 2: Both exponents are (3), so (n) is a perfect cube. Step 3: For a perfect cube, check exponents using (3).
Correct answer: C. 5
Explanation: Step 1: The prime factors are the base numbers. Step 2: Here (2,3,5) are prime factors, and the greatest is (5). Step 3: When the greatest prime factor is asked, do not choose a composite number.
Correct answer: B. 9
Explanation: Step 1: A factor divisible by (3) must have exponent of (3) at least (1). Step 2: The exponent of (2) has (3) choices (0,1,2), and exponent of (3) has (3) choices (1,2,3). Total (3 \times 3=9). Step 3: For conditional factors, adjust exponent choices carefully.
Correct answer: B. 8
Explanation: Step 1: A factor divisible by (10) must contain both (2) and (5). Step 2: The exponent of (2) can be (1) to (4), giving (4) choices, and the exponent of (5) can be (1) to (2), giving (2) choices. Total (4 \times 2=8). Step 3: Divisibility by (10) needs both prime factors.
Correct answer: A. 4
Explanation: Step 1: In a square factor, every prime exponent must be even. Step 2: For (2), choices are (0,2), so (2) choices; for (3), choices are (0,2), so (2) choices; for (5), only (0), so (1) choice. Total (2 \times 2 \times 1=4). Step 3: Count even exponent choices separately.
Correct answer: B. Fundamental theorem of arithmetic
Explanation: Step 1: Every integer greater than (1) has a unique prime factorisation apart from the order. Step 2: This comes from the fundamental theorem of arithmetic. Step 3: Remember uniqueness of prime factorisation with this theorem.
Correct answer: A. (1) has no prime factor
Explanation: Step 1: A prime number has exactly two positive factors. Step 2: (1) has only one positive factor, so it is not prime and has no prime factor. Step 3: Do not make the mistake of treating (1) as prime.