Which of the following statements is always true for sets?
Answer and explanation
Correct answer: \(A-(B\cup C)=(A-B)\cap(A-C)\)
An element belongs to \(A-(B\cup C)\) exactly when it is in A and is in neither B nor C. The same condition means that it belongs to both \(A-B\) and \(A-C\). Therefore, \(A-(B\cup C)=(A-B)\cap(A-C)\). This is a difference form of De Morgan’s law, so option C is always true.
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What is the correct answer to this question?
\(A-(B\cup C)=(A-B)\cap(A-C)\)
Why is this the correct answer?
An element belongs to \(A-(B\cup C)\) exactly when it is in A and is in neither B nor C. The same condition means that it belongs to both \(A-B\) and \(A-C\). Therefore, \(A-(B\cup C)=(A-B)\cap(A-C)\). This is a difference form of De Morgan’s law, so option C is always true.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).
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