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Which of the following is an irrational number that can be represented on the number line using the square-root construction method?

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Answer and explanation

Correct answer: \(\sqrt{7}\)

\(\sqrt{7}\) is irrational because 7 is not a perfect square. Since \(2^2<7<3^2\), its point lies between 2 and 3 and can be constructed using a square-root method. Exam tip: first check whether the radicand is a perfect square.

Related tags

Real NumbersNumber LineIrrational NumbersSquare Root ConstructionGeometry

Frequently asked questions

What is the correct answer to this question?

\(\sqrt{7}\)

Why is this the correct answer?

\(\sqrt{7}\) is irrational because 7 is not a perfect square. Since \(2^2<7<3^2\), its point lies between 2 and 3 and can be constructed using a square-root method. Exam tip: first check whether the radicand is a perfect square.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.

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