संख्या रेखा पर \(\sqrt{3}\) बनाने में समकोण त्रिभुज की कौन-सी भुजाएँ उपयोगी हो सकती हैं?
Which legs of a right triangle can be useful to construct \(\sqrt{3}\) on the number line?
Explanation opens after your attempt
A. \(\sqrt{2}\) और (1)\(\sqrt{2}\) and (1)
Concept
Because (\(\sqrt{2}\)2+12=3), the hypotenuse is \(\sqrt{3}\). Successive square roots are constructed using Pythagoras.
Why this answer is correct
The correct answer is A. \(\sqrt{2}\) और (1) / \(\sqrt{2}\) and (1). Because (\(\sqrt{2}\)2+12=3), the hypotenuse is \(\sqrt{3}\). Successive square roots are constructed using Pythagoras.
Exam Tip
क्योंकि (\(\sqrt{2}\)2+12=3), अतः कर्ण \(\sqrt{3}\) होगा। क्रमिक वर्गमूल बनाने में पाइथागोरस का प्रयोग होता है।
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