संख्या रेखा पर \(\sqrt{3}\) बनाने में समकोण त्रिभुज की कौन-सी भुजाएँ उपयोगी हो सकती हैं?

Which legs of a right triangle can be useful to construct \(\sqrt{3}\) on the number line?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}\) और (1)\(\sqrt{2}\) and (1)

Step 1

Concept

Because (\(\sqrt{2}\)2+12=3), the hypotenuse is \(\sqrt{3}\). Successive square roots are constructed using Pythagoras.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}\) और (1) / \(\sqrt{2}\) and (1). Because (\(\sqrt{2}\)2+12=3), the hypotenuse is \(\sqrt{3}\). Successive square roots are constructed using Pythagoras.

Step 3

Exam Tip

क्योंकि (\(\sqrt{2}\)2+12=3), अतः कर्ण \(\sqrt{3}\) होगा। क्रमिक वर्गमूल बनाने में पाइथागोरस का प्रयोग होता है।

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संख्या रेखा पर \(\sqrt{3}\) बनाने में समकोण त्रिभुज की कौन-सी भुजाएँ उपयोगी हो सकती हैं? / Which legs of a right triangle can be useful to construct \(\sqrt{3}\) on the number line?

Correct Answer: A. \(\sqrt{2}\) और (1) / \(\sqrt{2}\) and (1). Explanation: क्योंकि (\(\sqrt{2}\)2+12=3), अतः कर्ण \(\sqrt{3}\) होगा। क्रमिक वर्गमूल बनाने में पाइथागोरस का प्रयोग होता है। / Because (\(\sqrt{2}\)2+12=3), the hypotenuse is \(\sqrt{3}\). Successive square roots are constructed using Pythagoras.

Which concept should I revise for this Mathematics MCQ?

Because (\(\sqrt{2}\)2+12=3), the hypotenuse is \(\sqrt{3}\). Successive square roots are constructed using Pythagoras.

What exam hint can help solve this Mathematics question?

क्योंकि (\(\sqrt{2}\)2+12=3), अतः कर्ण \(\sqrt{3}\) होगा। क्रमिक वर्गमूल बनाने में पाइथागोरस का प्रयोग होता है।