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What is the roster form of J = {x : x = 2n + 1, n ∈ ℕ, n < 5}?

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Answer and explanation

Correct answer: J = {3, 5, 7, 9}

For n ∈ ℕ, taking the usual school convention ℕ = {1, 2, 3, ...}, the condition n < 5 gives n = 1, 2, 3, 4. Substituting these values in x = 2n + 1 gives 3, 5, 7, and 9. Therefore, the roster form is J = {3, 5, 7, 9}. The value n = 5 is excluded because the inequality is strict.

Tags

setsset-builder formroster formnatural numbersodd numbersSets and their representationsMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

J = {3, 5, 7, 9}

Why is this the correct answer?

For n ∈ ℕ, taking the usual school convention ℕ = {1, 2, 3, ...}, the condition n < 5 gives n = 1, 2, 3, 4. Substituting these values in x = 2n + 1 gives 3, 5, 7, and 9. Therefore, the roster form is J = {3, 5, 7, 9}. The value n = 5 is excluded because the inequality is strict.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Sets and their representations.

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