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What is the correct prime factorisation of 11025?
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Answer and explanation
Correct answer: (3^2\times5^2\times7^2)
Step 1: Recognise (11025=105^2). Step 2: Since (105=3\times5\times7), (11025=3^2\times5^2\times7^2). Step 3: In a square number, prime exponents are even.
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What is the correct answer to this question?
(3^2\times5^2\times7^2)
Why is this the correct answer?
Step 1: Recognise (11025=105^2). Step 2: Since (105=3\times5\times7), (11025=3^2\times5^2\times7^2). Step 3: In a square number, prime exponents are even.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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