संख्या रेखा पर \(-\sqrt{3}\) और \(-\sqrt{12}\) में कौन सा बिंदु दाईं ओर होगा?

On the number line, which point will be to the right, \(-\sqrt{3}\) or \(-\sqrt{12}\)?

Explanation opens after your attempt
Correct Answer

A. \(-\sqrt{3}\)

Step 1

Concept

Since \(\sqrt{12}>\sqrt{3}\), \(-\sqrt{3}\) is greater and lies to the right. In exams, negative signs reverse the comparison effect for square roots.

Step 2

Why this answer is correct

The correct answer is A. \(-\sqrt{3}\). Since \(\sqrt{12}>\sqrt{3}\), \(-\sqrt{3}\) is greater and lies to the right. In exams, negative signs reverse the comparison effect for square roots.

Step 3

Exam Tip

क्योंकि \(\sqrt{12}>\sqrt{3}\), इसलिए \(-\sqrt{3}\) बड़ा है और दाईं ओर होगा। परीक्षा में ऋणात्मक वर्गमूलों की तुलना करते समय चिह्न उल्टा प्रभाव देता है।

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Mathematics Answer, Explanation and Revision Hints

संख्या रेखा पर \(-\sqrt{3}\) और \(-\sqrt{12}\) में कौन सा बिंदु दाईं ओर होगा? / On the number line, which point will be to the right, \(-\sqrt{3}\) or \(-\sqrt{12}\)?

Correct Answer: A. \(-\sqrt{3}\). Explanation: क्योंकि \(\sqrt{12}>\sqrt{3}\), इसलिए \(-\sqrt{3}\) बड़ा है और दाईं ओर होगा। परीक्षा में ऋणात्मक वर्गमूलों की तुलना करते समय चिह्न उल्टा प्रभाव देता है। / Since \(\sqrt{12}>\sqrt{3}\), \(-\sqrt{3}\) is greater and lies to the right. In exams, negative signs reverse the comparison effect for square roots.

Which concept should I revise for this Mathematics MCQ?

Since \(\sqrt{12}>\sqrt{3}\), \(-\sqrt{3}\) is greater and lies to the right. In exams, negative signs reverse the comparison effect for square roots.

What exam hint can help solve this Mathematics question?

क्योंकि \(\sqrt{12}>\sqrt{3}\), इसलिए \(-\sqrt{3}\) बड़ा है और दाईं ओर होगा। परीक्षा में ऋणात्मक वर्गमूलों की तुलना करते समय चिह्न उल्टा प्रभाव देता है।