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In the geometric construction of ( \sqrt{2} ) on the number line, which length is taken as the hypotenuse?
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Answer and explanation
Correct answer: ( \sqrt{1^2+1^2})
With perpendicular sides (1) and (1), the hypotenuse is ( \sqrt{2}). Understand the construction using Pythagoras theorem.
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What is the correct answer to this question?
( \sqrt{1^2+1^2})
Why is this the correct answer?
With perpendicular sides (1) and (1), the hypotenuse is ( \sqrt{2}). Understand the construction using Pythagoras theorem.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
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