0 reads0 ratings0 helpful
If (x) is exactly midway between ( \sqrt{2} ) and ( \sqrt{8} ) on the number line, what is the value of (x)?
Advertisement
Answer and explanation
Correct answer: ( \frac{3\sqrt{2}}{2} )
The midpoint is ( \frac{\sqrt{2}+\sqrt{8}}{2}=\frac{\sqrt{2}+2\sqrt{2}}{2}=\frac{3\sqrt{2}}{2} ). Take the average of the two values for the midpoint.
Frequently asked questions
What is the correct answer to this question?
( \frac{3\sqrt{2}}{2} )
Why is this the correct answer?
The midpoint is ( \frac{\sqrt{2}+\sqrt{8}}{2}=\frac{\sqrt{2}+2\sqrt{2}}{2}=\frac{3\sqrt{2}}{2} ). Take the average of the two values for the midpoint.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement