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If \(U=\{1,2,3,4,5,6,7\}\) and \(A=\{2,4,7\}\), how many elements are in \(\mathcal{P}(A')\)?

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Answer and explanation

Correct answer: 16

First find the complement relative to \(U\): \(A'=U\setminus A=\{1,3,5,6\}\). Thus \(A'\) has four elements. A finite set with \(n\) elements has \(2^n\) subsets, so its power set has \(2^4=16\) elements. Therefore \(n(\mathcal{P}(A'))=16\), and option C is correct. The answer is not just the number of elements in \(A'\); it counts all its subsets.

Tags

setspower_setcomplementcardinalityPower Set and SubsetsMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

16

Why is this the correct answer?

First find the complement relative to \(U\): \(A'=U\setminus A=\{1,3,5,6\}\). Thus \(A'\) has four elements. A finite set with \(n\) elements has \(2^n\) subsets, so its power set has \(2^4=16\) elements. Therefore \(n(\mathcal{P}(A'))=16\), and option C is correct. The answer is not just the number of elements in \(A'\); it counts all its subsets.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Power Set and Subsets.

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