If the point \(P\) on the number line represents the number \(\sqrt{49}+\sqrt{16}\), what is the coordinate of \(P\)?
Answer and explanation
Correct answer: 11
Since \(\sqrt{49}=7\) and \(\sqrt{16}=4\), we get \(\sqrt{49}+\sqrt{16}=7+4=11\). Therefore, the coordinate of point \(P\) on the number line is \(11\). The value 65 is the product \(7\times 4\), not the required sum. Exam tip: evaluate each square root first and then perform the indicated operation.
Frequently asked questions
What is the correct answer to this question?
11
Why is this the correct answer?
Since \(\sqrt{49}=7\) and \(\sqrt{16}=4\), we get \(\sqrt{49}+\sqrt{16}=7+4=11\). Therefore, the coordinate of point \(P\) on the number line is \(11\). The value 65 is the product \(7\times 4\), not the required sum. Exam tip: evaluate each square root first and then perform the indicated operation.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
