If point P is located at \\(\sqrt{196}-\sqrt{81}\\) on the number line, what is the coordinate of P?
Answer and explanation
Correct answer: 5
Since \(\sqrt{196}=14\) and \(\sqrt{81}=9\), we get \(\sqrt{196}-\sqrt{81}=14-9=5\). Therefore, the coordinate of P is 5. Option D gives only the first square root and ignores the subtraction. Exam tip: evaluate the square roots first, then perform the indicated operation.
Frequently asked questions
What is the correct answer to this question?
5
Why is this the correct answer?
Since \(\sqrt{196}=14\) and \(\sqrt{81}=9\), we get \(\sqrt{196}-\sqrt{81}=14-9=5\). Therefore, the coordinate of P is 5. Option D gives only the first square root and ignores the subtraction. Exam tip: evaluate the square roots first, then perform the indicated operation.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
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