If n(U) = 90, n(Aᶜ) = 35, n(Bᶜ) = 50, and n(Aᶜ ∩ Bᶜ) = 18, what is n(A ∩ B)?
Answer and explanation
Correct answer: 23
First find the cardinality of Aᶜ ∪ Bᶜ using the inclusion–exclusion formula: n(Aᶜ ∪ Bᶜ) = n(Aᶜ) + n(Bᶜ) − n(Aᶜ ∩ Bᶜ) = 35 + 50 − 18 = 67. By De Morgan’s law, Aᶜ ∪ Bᶜ = (A ∩ B)ᶜ. Therefore, n((A ∩ B)ᶜ) = 67. Since the universal set has 90 elements, n(A ∩ B) = 90 − 67 = 23. Hence, option A is correct.
Frequently asked questions
What is the correct answer to this question?
23
Why is this the correct answer?
First find the cardinality of Aᶜ ∪ Bᶜ using the inclusion–exclusion formula: n(Aᶜ ∪ Bᶜ) = n(Aᶜ) + n(Bᶜ) − n(Aᶜ ∩ Bᶜ) = 35 + 50 − 18 = 67. By De Morgan’s law, Aᶜ ∪ Bᶜ = (A ∩ B)ᶜ. Therefore, n((A ∩ B)ᶜ) = 67. Since the universal set has 90 elements, n(A ∩ B) = 90 − 67 = 23. Hence, option A is correct.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Complement of a Set and Its Properties.