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If n(A ∪ B) = 54, n(A \ B) = 17, and n(B \ A) = 21, what is n(A ∩ B)?

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Answer and explanation

Correct answer: 16

The union A ∪ B consists of three mutually disjoint regions: the elements only in A, the elements only in B, and the elements common to both sets. Therefore, n(A ∪ B) = n(A \ B) + n(B \ A) + n(A ∩ B). Substituting the values gives 54 = 17 + 21 + n(A ∩ B), so n(A ∩ B) = 54 − 38 = 16. Hence, option A is correct.

Tags

setsunionintersectionset differencecardinalityvenn diagramsOperations on Sets (UnionDifference)operations on sets union intersection difference

Frequently asked questions

What is the correct answer to this question?

16

Why is this the correct answer?

The union A ∪ B consists of three mutually disjoint regions: the elements only in A, the elements only in B, and the elements common to both sets. Therefore, n(A ∪ B) = n(A \ B) + n(B \ A) + n(A ∩ B). Substituting the values gives 54 = 17 + 21 + n(A ∩ B), so n(A ∩ B) = 54 − 38 = 16. Hence, option A is correct.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).

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