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If n(A ∪ B) = 45, n(A) = 28, and n(B) = 25, find n(A ∩ B).

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Answer and explanation

Correct answer: 8

Use the two-set inclusion–exclusion formula: n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Rearranging gives n(A ∩ B) = n(A) + n(B) − n(A ∪ B). Substituting the data, n(A ∩ B) = 28 + 25 − 45 = 53 − 45 = 8. Thus option A is correct. The value 12 does not follow from the formula, 17 is an incorrect subtraction, and 53 is merely n(A) + n(B) before correcting for overlap.

Tags

setscardinalityintersectioninclusion-exclusionOperations on Sets (UnionDifference)operations on sets union intersection differenceMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

8

Why is this the correct answer?

Use the two-set inclusion–exclusion formula: n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Rearranging gives n(A ∩ B) = n(A) + n(B) − n(A ∪ B). Substituting the data, n(A ∩ B) = 28 + 25 − 45 = 53 − 45 = 8. Thus option A is correct. The value 12 does not follow from the formula, 17 is an incorrect subtraction, and 53 is merely n(A) + n(B) before correcting for overlap.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).

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