If n(A ∪ B) = 126, n(A − B) = 47, and n(B − A) = 39, what is n(A ∩ B)?
Answer and explanation
Correct answer: 40
The union A ∪ B is divided into three disjoint regions: the elements only in A, counted by n(A − B) = 47; the elements only in B, counted by n(B − A) = 39; and the common elements, counted by n(A ∩ B). Therefore, 126 = 47 + 39 + n(A ∩ B), so n(A ∩ B) = 126 − 86 = 40. Hence, option A is correct.
Frequently asked questions
What is the correct answer to this question?
40
Why is this the correct answer?
The union A ∪ B is divided into three disjoint regions: the elements only in A, counted by n(A − B) = 47; the elements only in B, counted by n(B − A) = 39; and the common elements, counted by n(A ∩ B). Therefore, 126 = 47 + 39 + n(A ∩ B), so n(A ∩ B) = 126 − 86 = 40. Hence, option A is correct.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).