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If n(A) = 69, n(B) = 74, and n(A − B) = 28, what is n(A ∪ B)?

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Answer and explanation

Correct answer: 102

The set A is the disjoint union of A − B and A ∩ B. Thus n(A ∩ B) = n(A) − n(A − B) = 69 − 28 = 41. Now apply the union formula: n(A ∪ B) = n(A) + n(B) − n(A ∩ B) = 69 + 74 − 41 = 102. The value 143 incorrectly counts the common elements twice, while 41 is only the intersection. Therefore option A is correct.

Tags

setsunionintersectionset-differenceinclusion-exclusionOperations on Sets (UnionDifference)operations on sets union intersection differenceMathematics

Frequently asked questions

What is the correct answer to this question?

102

Why is this the correct answer?

The set A is the disjoint union of A − B and A ∩ B. Thus n(A ∩ B) = n(A) − n(A − B) = 69 − 28 = 41. Now apply the union formula: n(A ∪ B) = n(A) + n(B) − n(A ∩ B) = 69 + 74 − 41 = 102. The value 143 incorrectly counts the common elements twice, while 41 is only the intersection. Therefore option A is correct.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).

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