If n(A) = 42, n(B) = 38, and n(A ∩ B) = 17, what is n(A' ∩ B)?
Answer and explanation
Correct answer: 21
The set A' ∩ B contains elements that are in B but not in A. This is the same as B − A. Set B has 38 elements, and 17 of them are also in A, because n(A ∩ B) = 17. Removing these common elements leaves 38 − 17 = 21 elements. Therefore n(A' ∩ B) = 21.
Frequently asked questions
What is the correct answer to this question?
21
Why is this the correct answer?
The set A' ∩ B contains elements that are in B but not in A. This is the same as B − A. Set B has 38 elements, and 17 of them are also in A, because n(A ∩ B) = 17. Removing these common elements leaves 38 − 17 = 21 elements. Therefore n(A' ∩ B) = 21.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).