If n(A) = 18, n(B) = 22, and n(A ∪ B) = 31, what is n(A \ B)?
Answer and explanation
Correct answer: 9
Use the inclusion–exclusion formula n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Thus, 31 = 18 + 22 − n(A ∩ B), so n(A ∩ B) = 9. The difference A \ B contains the elements of A that are not in B, so n(A \ B) = n(A) − n(A ∩ B) = 18 − 9 = 9. Therefore, option A is correct.
Frequently asked questions
What is the correct answer to this question?
9
Why is this the correct answer?
Use the inclusion–exclusion formula n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Thus, 31 = 18 + 22 − n(A ∩ B), so n(A ∩ B) = 9. The difference A \ B contains the elements of A that are not in B, so n(A \ B) = n(A) − n(A ∩ B) = 18 − 9 = 9. Therefore, option A is correct.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).