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If n(A) = 16, n(B) = 13, and n(A ∪ B) = 21, what is n(A ∩ B)?

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Answer and explanation

Correct answer: 8

For two finite sets, the addition rule is n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Substituting the given values gives 21 = 16 + 13 − n(A ∩ B). Therefore n(A ∩ B) = 29 − 21 = 8. The subtraction is necessary because elements common to A and B are counted twice when n(A) and n(B) are added.

Tags

setscardinalityinclusion exclusionintersectionOperations on Sets (UnionDifference)operations on sets union intersection differenceMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

8

Why is this the correct answer?

For two finite sets, the addition rule is n(A ∪ B) = n(A) + n(B) − n(A ∩ B). Substituting the given values gives 21 = 16 + 13 − n(A ∩ B). Therefore n(A ∩ B) = 29 − 21 = 8. The subtraction is necessary because elements common to A and B are counted twice when n(A) and n(B) are added.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).

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