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If K = {x : x = 3n + 1, n ∈ N, n ≤ 5}, where N = {1, 2, 3, ...}, what type of set is K?

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Answer and explanation

Correct answer: Finite set

Because n is a natural number and n ≤ 5, its possible values are only 1, 2, 3, 4, and 5. The corresponding values of x = 3n + 1 are 4, 7, 10, 13, and 16. Thus K = {4, 7, 10, 13, 16}, which has five elements and is therefore finite. The upper bound on n is decisive.

Tags

setsfinite setbounded variableset-builder formThe Empty SetFinite and Infinite SetsEqual Setsthe empty set finite and infinite sets equal setsMathematicsClass 10 MCQ

Frequently asked questions

What is the correct answer to this question?

Finite set

Why is this the correct answer?

Because n is a natural number and n ≤ 5, its possible values are only 1, 2, 3, 4, and 5. The corresponding values of x = 3n + 1 are 4, 7, 10, 13, and 16. Thus K = {4, 7, 10, 13, 16}, which has five elements and is therefore finite. The upper bound on n is decisive.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: The Empty Set, Finite and Infinite Sets, Equal Sets.

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