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If F = {x : x ∈ ℤ, |x + 1| ≤ 2}, what is the number of elements in F?

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Answer and explanation

Correct answer: 5

The condition |x + 1| ≤ 2 means that x + 1 lies between −2 and 2, inclusive. Therefore, −2 ≤ x + 1 ≤ 2. Subtracting 1 from all three parts gives −3 ≤ x ≤ 1. Since x must be an integer, the possible values are −3, −2, −1, 0, and 1. There are 5 values, so the set F has 5 elements. The endpoints are included because the inequality is ‘less than or equal to’.

Tags

setsfinite setcardinalityabsolute valueintegersThe Empty SetFinite and Infinite SetsEqual Setsthe empty set finite and infinite sets equal setsMathematics

Frequently asked questions

What is the correct answer to this question?

5

Why is this the correct answer?

The condition |x + 1| ≤ 2 means that x + 1 lies between −2 and 2, inclusive. Therefore, −2 ≤ x + 1 ≤ 2. Subtracting 1 from all three parts gives −3 ≤ x ≤ 1. Since x must be an integer, the possible values are −3, −2, −1, 0, and 1. There are 5 values, so the set F has 5 elements. The endpoints are included because the inequality is ‘less than or equal to’.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: The Empty Set, Finite and Infinite Sets, Equal Sets.

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