If \(A=\{x:x\text{ is a vowel in English}\}\) and \(B=\{a,e,i\}\), then, using \(B\subseteq A\), what is \(A\cup B\)?
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Answer and explanation
Correct answer: \(\{a,e,i,o,u\}\)
The vowels in English are \(A=\{a,e,i,o,u\}\). The set \(B=\{a,e,i\}\) is a subset of \(A\), so every element of \(B\) is already present in \(A\). Taking the union adds no new element; therefore \(A\cup B=A=\{a,e,i,o,u\}\). Option B is only the smaller subset, not the union.
Frequently asked questions
What is the correct answer to this question?
\(\{a,e,i,o,u\}\)
Why is this the correct answer?
The vowels in English are \(A=\{a,e,i,o,u\}\). The set \(B=\{a,e,i\}\) is a subset of \(A\), so every element of \(B\) is already present in \(A\). Taking the union adds no new element; therefore \(A\cup B=A=\{a,e,i,o,u\}\). Option B is only the smaller subset, not the union.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).
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