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If A = {x ∈ ℤ : −3 ≤ x ≤ 4} and B = {x ∈ ℤ : x² < 10}, what is A \ B?

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Answer and explanation

Correct answer: {4}

First list the integers in A: A = {−3, −2, −1, 0, 1, 2, 3, 4}. For B, the condition x² < 10 means −√10 < x < √10, so the integer elements are B = {−3, −2, −1, 0, 1, 2, 3}. The set difference A \ B keeps elements of A that are not in B. Therefore, only 4 remains, and A \ B = {4}.

Tags

setsset-builder notationintegersset differenceoperations on setsOperations on Sets (UnionIntersectionDifference)operations on sets union intersection differenceMathematics

Frequently asked questions

What is the correct answer to this question?

{4}

Why is this the correct answer?

First list the integers in A: A = {−3, −2, −1, 0, 1, 2, 3, 4}. For B, the condition x² < 10 means −√10 < x < √10, so the integer elements are B = {−3, −2, −1, 0, 1, 2, 3}. The set difference A \ B keeps elements of A that are not in B. Therefore, only 4 remains, and A \ B = {4}.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Sets. Topic: Operations on Sets (Union, Intersection, Difference).

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