If A = {x : x is a natural-number divisor of 15} and C = {1, 3, 5}, which relation is correct?
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Answer and explanation
Correct answer: C ⊂ A and C ≠ A
The natural-number divisors of 15 are A = {1, 3, 5, 15}. Every element of C = {1, 3, 5} is present in A, so C is a subset of A. However, C does not contain 15, which belongs to A, so the two sets are not equal. Hence C is a proper subset of A, written C ⊂ A and C ≠ A. Therefore option A is correct.
Frequently asked questions
What is the correct answer to this question?
C ⊂ A and C ≠ A
Why is this the correct answer?
The natural-number divisors of 15 are A = {1, 3, 5, 15}. Every element of C = {1, 3, 5} is present in A, so C is a subset of A. However, C does not contain 15, which belongs to A, so the two sets are not equal. Hence C is a proper subset of A, written C ⊂ A and C ≠ A. Therefore option A is correct.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Sets. Topic: Equal sets and Subsets.
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