If \(A=-\sqrt{28}\), \(B=-5.3\), and \(C=-\frac{16}{3}\), which of these numbers is located farthest to the left on the number line?
Answer and explanation
Correct answer: C
Since \(\sqrt{28}\approx 5.292\), we get \(A\approx -5.292\). Also, \(B=-5.3\) and \(C=-\frac{16}{3}\approx -5.333\). Among negative numbers, the smaller number lies farther to the left on the number line. Thus, \(-5.333<-5.3<-5.292\), so \(C\) is farthest left. Exam tip: When comparing negative numbers, the one with the greater magnitude is the smaller number.
Frequently asked questions
What is the correct answer to this question?
C
Why is this the correct answer?
Since \(\sqrt{28}\approx 5.292\), we get \(A\approx -5.292\). Also, \(B=-5.3\) and \(C=-\frac{16}{3}\approx -5.333\). Among negative numbers, the smaller number lies farther to the left on the number line. Thus, \(-5.333<-5.3<-5.292\), so \(C\) is farthest left. Exam tip: When comparing negative numbers, the one with the greater magnitude is the smaller number.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
